-sin^2(2x)+4cos^2x=0

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Solution for -sin^2(2x)+4cos^2x=0 equation: 


Simplifying
-1sin2(2x) + 4cos2x = 0

Remove parenthesis around (2x)
-1in2s * 2x + 4cos2x = 0

Reorder the terms for easier multiplication:
-1 * 2in2s * x + 4cos2x = 0

Multiply -1 * 2
-2in2s * x + 4cos2x = 0

Multiply in2s * x
-2in2sx + 4cos2x = 0

Reorder the terms:
4cos2x + -2in2sx = 0

Solving
4cos2x + -2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2in2sx' to each side of the equation.
4cos2x + -2in2sx + 2in2sx = 0 + 2in2sx

Combine like terms: -2in2sx + 2in2sx = 0
4cos2x + 0 = 0 + 2in2sx
4cos2x = 0 + 2in2sx
Remove the zero:
4cos2x = 2in2sx

Divide each side by '4os2x'.
c = 0.5in2o-1s-1

Simplifying
c = 0.5in2o-1s-1

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